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set.issuperset()

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Definition
Report whether this set contains another set.

Syntax
set(x).issuperset(y)

Parameter
x,y=set

Example
The output is:
 set1={3,1,44,66}
set2={1,44,66}
set3=set1.issuperset(set2)
print(set3)

>>> 
True
>>>

set.issuperset()
The equal to following result:
 >>> from decimal import Decimal
>>> a=set()
>>> a.add(Decimal(1).adjusted())
>>> a.add(Decimal(.55).canonical())
>>> a.add(Decimal(-1).compare_signal(1))
>>> a
{0, Decimal('0.5500000000000000444089209850062616169452667236328125'), Decimal('-1')}
>>> b=set()
>>> b.add(Decimal(1).compare_total(2))
>>> b.add(Decimal(0.1).copy_abs())
>>> b
{Decimal('0.1000000000000000055511151231257827021181583404541015625'), Decimal('-1')}
>>> a.issuperset(b)
False

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