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math.sqrt()

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Definition
Return the square root of value requested.

Syntax
math.sqrt(x)

Parameters
x=number

Examples
The method come up with:
 import math
>>> math.sqrt(44)
6.6332495807108
>>> math.sqrt(33)
5.744562646538029
>>> 
>>> math.sqrt(49)
7.0
>>> 

for statement
Method run the loop for sets.
import math
set1={math.trunc(1.1),math.sqrt(49),math.pow(4,2),math.e,math.exp(44)}
set2={math.floor(3.12),math.fmod(3,2),math.fabs(22), math.ceil(1)}
for i in map(lambda a,b: a+b, set1, set2):
print(i)

>>> 
17.0
4
24.718281828459045
>>>


if statement sum(map(lamda))__lt__(value()
If statement returns that the sum of the x/y is not less than 2.
 import math
x={math.factorial(81),math.sqrt(49),math.pow(4,2),math.e,math.exp(44)}
y={math.floor(3.12),math.fmod(3,2),math.fabs(22), math.ceil(1)}
if sum(map(lambda a,b: a/b, x,y)).__lt__(2):
                                                        print("The sum of x and y is less than 2")
else:
       print("The sum of x and y is greater than 2.")
>>> 
The sum is greater than 2.
>>>







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